عدد حقيقي يزيد عن معكوسه الضربي بمقدار 5/6 نفرض أن العدد س ومعكوسه س/1
س=س/1+5/6 بالضرب في س
س*2=1+5/6س وبحل المعادلة التربيعية نجد أن العدادان هما
س=3/2 وعليه فإن معكوسه الضربي 2/3 أو س=2/3- وعليه فإن معكوسه الضربي 3/2-
Assuming a real number is greater than its reciprocal by 5/6, let the number be represented as s and its reciprocal as 1/s. Therefore, s = 1/s + 5/6. By multiplying s on both sides, we get s^2 = 1 + 5/6s. Solving the quadratic equation, we find that the numbers are s = 3/2 and its reciprocal is 2/3. Therefore, the reciprocal of 3/2 is 2/3, or s = 2/3. Hence, the reciprocal of 3/2 is 2/3.
